(1/2n^2)-(1/5n)=3

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Solution for (1/2n^2)-(1/5n)=3 equation: 


n in (-oo:+oo)

(1/2)*n^2-((1/5)*n) = 3 // - 3

(1/2)*n^2-((1/5)*n)-3 = 0

(1/2)*n^2+(-1/5)*n-3 = 0

1/2*n^2-1/5*n-3 = 0

DELTA = (-1/5)^2-(-3*1/2*4)

DELTA = 151/25

DELTA > 0

n = ((151/25)^(1/2)+1/5)/(1/2*2) or n = (1/5-(151/25)^(1/2))/(1/2*2)

n = (151/25)^(1/2)+1/5 or n = 1/5-(151/25)^(1/2)

n in { 1/5-(151/25)^(1/2), (151/25)^(1/2)+1/5 }

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